1. A teacher can divide her class into groups into groups of 5,13 and 17. What is the smallest possible strength of the class?

a.835

b.940

c.1105

d.1220

Answer: C

Explanation:

For smallest possible class strength, we consider LCM of the given numbers. So LCM (5, 13, 17) = 1105.

2. If QUESTION = DOMESTIC what will b code for RESPONSE ?

1. OMESUCEM

2. OMESICSM

3. OMESICEM

4. OMESISCM

Answer : 3

Explanation:

Q U E S T I O N

D O M E S T I C

We can see in the word 'RESPONSE' only R and P are the letters whose code is not given, by having a look on options we can say code for R is O and code for P is S (because common in all options).

Now we can easily code the word 'RESPONSE'as 'OMESICEM'.

3. A box contains 90 bolts each of 100 gm and 100 bolts each of 150 gm. If the entire box weighs 35.5 kg., then the weight of the empty box is :

A. 10 kg

B. 10.5 kg

C. 11 kg

D. 11.5 kg

E. None of the above

Answer: B

Explanation:

Let the weight of Empty box be x

90 × 0.100 + 100 × 0.150 + x = 35.5

Then x = 10.5 kg

4. The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member. Find how much younger is the new member?

Answer: 40

Explanation:

Let the average of all 10 members 4 years ago was x. After 4 years, 10 members age increases by 10 × 4 = 40. But there is no change in the average as a person is replaced by an younger one. Which means, the younger one age is 40 years less than the old one.

5. If the radius of a circle is increased by 20% then the area is increased by:

a) 44%

a.835

b.940

c.1105

d.1220

Answer: C

Explanation:

For smallest possible class strength, we consider LCM of the given numbers. So LCM (5, 13, 17) = 1105.

2. If QUESTION = DOMESTIC what will b code for RESPONSE ?

1. OMESUCEM

2. OMESICSM

3. OMESICEM

4. OMESISCM

Answer : 3

Explanation:

Q U E S T I O N

D O M E S T I C

We can see in the word 'RESPONSE' only R and P are the letters whose code is not given, by having a look on options we can say code for R is O and code for P is S (because common in all options).

Now we can easily code the word 'RESPONSE'as 'OMESICEM'.

3. A box contains 90 bolts each of 100 gm and 100 bolts each of 150 gm. If the entire box weighs 35.5 kg., then the weight of the empty box is :

A. 10 kg

B. 10.5 kg

C. 11 kg

D. 11.5 kg

E. None of the above

Answer: B

Explanation:

Let the weight of Empty box be x

90 × 0.100 + 100 × 0.150 + x = 35.5

Then x = 10.5 kg

4. The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member. Find how much younger is the new member?

Answer: 40

Explanation:

Let the average of all 10 members 4 years ago was x. After 4 years, 10 members age increases by 10 × 4 = 40. But there is no change in the average as a person is replaced by an younger one. Which means, the younger one age is 40 years less than the old one.

5. If the radius of a circle is increased by 20% then the area is increased by:

a) 44%

b) 120%

c) 144%

d) 40%

e) None of the above

Answer: a

Explanation:

Let say radius = $\pi {r^2}$ = $\pi {10^2}$ = $100\pi $

New radius = 10 × 120% = 12

New area = $\pi {12^2}$ = $144\pi $

Increment = $\dfrac{{144\pi - 100\pi }}{{100\pi }} \times 100$ = 44%

New radius = 10 × 120% = 12

New area = $\pi {12^2}$ = $144\pi $

Increment = $\dfrac{{144\pi - 100\pi }}{{100\pi }} \times 100$ = 44%

6. When Raja was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Raja’s brother is 6 years older than Raja and his mother is 3 years younger than his father, how old was Raja’s sister when Raja was born?

Answer: 10 year

Explanation:

Raja's brother 6 year old when Raja was born.

His father's age = 32 + 6 = 38 year

His mother's age = 35 year

His sister age =35 – 25 = 10 years

7. A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:

Answer:

Explanation:

Cost price = 400

Gain% = 20%

Gain = 400 × $\dfrac{{20}}{{100}}$ = 80

Cost price = 400 + 80 = 480

8.If

1111 = r

2222 = t

3333 = e

4444 = n

5555 = ?

Answer:

Explanation:

1 + 1 + 1 + 1 = 4

Four last letter is r

Similarly

5 + 5 + 5 + 5 = 20 i.e twenty so ans is Y.

9. A new apartment complex purchased 60 toilets and 20 shower heads. If the price of a toilet is three times the price of a shower head, what percent of the total cost was the cost of all the shower heads?

a) 9%

b) 10%

c) 11%

d) 13%

e) 15%

Explanation:

Raja's brother 6 year old when Raja was born.

His father's age = 32 + 6 = 38 year

His mother's age = 35 year

His sister age =35 – 25 = 10 years

7. A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:

Answer:

Explanation:

Cost price = 400

Gain% = 20%

Gain = 400 × $\dfrac{{20}}{{100}}$ = 80

Cost price = 400 + 80 = 480

8.If

1111 = r

2222 = t

3333 = e

4444 = n

5555 = ?

Answer:

Explanation:

1 + 1 + 1 + 1 = 4

Four last letter is r

Similarly

5 + 5 + 5 + 5 = 20 i.e twenty so ans is Y.

9. A new apartment complex purchased 60 toilets and 20 shower heads. If the price of a toilet is three times the price of a shower head, what percent of the total cost was the cost of all the shower heads?

a) 9%

b) 10%

c) 11%

d) 13%

e) 15%

Answer:b

Explanation:

Let the cost of shower head is x. Then the cost of the toilet = 3x.

Total cost of 60 toilets and 20 shower heads = 60 × 3x + 20 × x = 200x

So shower heads cost as a percentage of total cost = $\dfrac{{20x }}{{20x}}$ × 100 = 10%

10. Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively.

Answer: 776

Required number= 780 – 4 = 776

Let the cost of shower head is x. Then the cost of the toilet = 3x.

Total cost of 60 toilets and 20 shower heads = 60 × 3x + 20 × x = 200x

So shower heads cost as a percentage of total cost = $\dfrac{{20x }}{{20x}}$ × 100 = 10%

10. Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively.

Answer: 776

Explanation:

LCM of (26,39,52,65) = 780Required number= 780 – 4 = 776

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